Asked by Invincible
At what height above the earth's surface. the acceleration due to gravity will be 1/9th of its value at the earth's surface. Re = 6400km
Answers
Answered by
Damon
(1/3)^2 = 1/9
so
r = 3 re from earth center=19200
subtract re to get above surface
so 19200-6400= 12800 km
so
r = 3 re from earth center=19200
subtract re to get above surface
so 19200-6400= 12800 km
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