Ask a New Question

Question

2 boats left the harbour at the same time. One travelled at 10km/h on a course of 47 degrees. from the north. the other travelled 8km/h on a course of 79 degrees. how far apart were the boats after 45 minutes to th nearest tenth of a kilometre.
12 years ago

Answers

Steve
the angle between their courses is 32°
using the law of cosines, the distance between the ships is thus

d^2 = (10*3/4)^2 + (8*3/4)^2 - 2*(10*3/4)(8*3/4) cos 32°
d^2 = 15.93
d = 4.0 km
12 years ago

Related Questions

Two Boats left the harbour at the same time. One travelled at 10km/h on a bearing of N47°E. The othe... Two boats leave whitby harbour at the same time one boat heads 18 km to it's destination and the oth... two boats A and B left a port C at the same time on different routes. B travelled on a bearing of... two boats, A and B, left a port C at the same time on different routes. B travelled on a bearing of... Two boats A and B left a port C at the same time on different route .B travelled on a bearing... two boats a and left a port c at the same time on different route b travelled on a bearing of 150 an... A ship left harbour A and travelled for 20km on a bearing of 125°. It then changed course of 035° fo... A sailing ship left harbour A and travelled 20km on a bearing of 125 degrees. It then changed course... two boats left the harbour at the same time. one travelled at 15km/h on a course of 170 degrees for...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use