Asked by claire
2 boats left the harbour at the same time. One travelled at 10km/h on a course of 47 degrees. from the north. the other travelled 8km/h on a course of 79 degrees. how far apart were the boats after 45 minutes to th nearest tenth of a kilometre.
Answers
Answered by
Steve
the angle between their courses is 32°
using the law of cosines, the distance between the ships is thus
d^2 = (10*3/4)^2 + (8*3/4)^2 - 2*(10*3/4)(8*3/4) cos 32°
d^2 = 15.93
d = 4.0 km
using the law of cosines, the distance between the ships is thus
d^2 = (10*3/4)^2 + (8*3/4)^2 - 2*(10*3/4)(8*3/4) cos 32°
d^2 = 15.93
d = 4.0 km
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.