Question
A 250-g block of ice is removed from the refrigerator at 8.0°C. How much heat does the ice absorb as it warms to room temperature (22°C)? The heat of fusion of water is 3.34105 J/kg.
Answers
drwls
I do not recognize the square symbols you are typing.
Is ��8.0°C the same as -8.0 C ?
Is 3.34��105 the same as 3.34*10^5 ?
You will also need the specific heats of ice and liquid water.
Is ��8.0°C the same as -8.0 C ?
Is 3.34��105 the same as 3.34*10^5 ?
You will also need the specific heats of ice and liquid water.
hana
Q=mHf
=0.25x3.34x10^5=83500J
=0.25x3.34x10^5=83500J