Asked by yasir

A 250-g block of ice is removed from the refrigerator at 􏰀8.0°C. How much heat does the ice absorb as it warms to room temperature (22°C)? The heat of fusion of water is 3.34􏰁105 J/kg.
Answered by drwls
I do not recognize the square symbols you are typing.

Is ��8.0°C the same as -8.0 C ?
Is 3.34��105 the same as 3.34*10^5 ?

You will also need the specific heats of ice and liquid water.
Answered by hana
Q=mHf
=0.25x3.34x10^5=83500J
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