Asked by Brenda

When 90 kJ is removed from a 2-kg copper bar its temperature drops from 200 degrees celcius to 85 degrees celcius what is the specific heat of the iron?


Answered by drwls
Q = M*C*(delta T)

Solve for C, with

deltaT = -115 C
Q = -90 kJ
M = 2.0 kg
Answered by Bo
0.391
Answered by Bo
0.39 kJ/kg degree C
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