Asked by Emma
How many atoms of carbon are contained in 47.6 g of Al2(CO3)3? The molar mass of Al2(CO3)3 is 233.99 g/mol.
Answers
Answered by
DrBob222
mols Al2(CO3)3 = grams/molar mass
Atoms C = 3x that.
Atoms C = 3x that.
Answered by
Austin
DrBob222 is wrong and you wouldn't ask if you didn't need the answer.
take molar mass of C/molar mass of Al2(CO3)3, multiply that by 47.6 g, and then multiply that by avogadro's number (6.022*10^23) = 1.23*10^23
take molar mass of C/molar mass of Al2(CO3)3, multiply that by 47.6 g, and then multiply that by avogadro's number (6.022*10^23) = 1.23*10^23
Answered by
Sarthak
3.68x10^23 C atoms
Answered by
Anonymous
ratio
Answered by
Anonymous
sarthak is correct
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