Asked by Allie
1.) How many carbon atoms are contained in a 1.500 carat diamond (carbon) if 1 caret =200.0 mg?
_____________________________
I don't know if I'm doing this right but I tried. Can someone help?
1.500 carat diamond (C) *(200.0 mg/1 caret) ...
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3.) Magnesium has a sensity of 1.74 g/cm^3. How many atoms of magnesium are contained in a volume of 12.0 cm^3?
Because they give the Density & Volume, I found the mass but i'm not sure how to do the rest.
DV=M; (1.74g/cm^3)(12.0cm^3)=20.88g
_____________________________
I don't know if I'm doing this right but I tried. Can someone help?
1.500 carat diamond (C) *(200.0 mg/1 caret) ...
__________________________________
3.) Magnesium has a sensity of 1.74 g/cm^3. How many atoms of magnesium are contained in a volume of 12.0 cm^3?
Because they give the Density & Volume, I found the mass but i'm not sure how to do the rest.
DV=M; (1.74g/cm^3)(12.0cm^3)=20.88g
Answers
Answered by
DrBob222
1. What yu have gives you mg C. Convert that to grams, then to mols, then to atoms remembering there are 6.02E23 atoms in 1 mole.
2. You have mass Mg. Convert to mols, then to atoms.
2. You have mass Mg. Convert to mols, then to atoms.
Answered by
Allie
Here are my answers after I figured it out. Are these correct though?
1.) 1.50 *10^25 atoms C
2.) 5.173 *10^23 atoms Mg
1.) 1.50 *10^25 atoms C
2.) 5.173 *10^23 atoms Mg
Answered by
DrBob222
1 is no. Post your work and I'll find the error. Follow my steps. I suspect you didn't convert mg to grams.
2. ok
2. ok
Answered by
Allie
1.) Here is what I did.
1.500 carat diamond (C) * (200.0 mg C/1 caret diamond C) * (1 g C/ 1,000 mg C) *( 1 mol C / 12.011 g C) * (6.022*10^23 atoms C/ 1 mol C)
Sorry its confusing when you type it
1.500 carat diamond (C) * (200.0 mg C/1 caret diamond C) * (1 g C/ 1,000 mg C) *( 1 mol C / 12.011 g C) * (6.022*10^23 atoms C/ 1 mol C)
Sorry its confusing when you type it
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