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Show that one mole of KCLO3 contains 122.55 grams.

2 KCLO3(s)->2 KCL(s) + 3 O2(g)

1 answer

K = 39.1 or thereabouts
Cl = 35.4 about
O = 3*16 = 48 about.
You can look up these numbers and add them.
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