In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

a. Find the percent of increase in the newspaper’s circulation from 2000 to 2001 and from 2001 to 2002.
b. Which period had a higher percent of increase, 2000 to 2001, or 2001 to 2002? (3 points)

Is my answer correct?

2000 - 2001: 3640 - 3250 = 390
2001 - 2002: 4100 - 3640 = 460

2001 to 2002 had the higher percent of increase.

4 answers

It is difference divided by start
So now you need to take the 390 and divide by 3250
And take the 450 and divide by 3640

390 and 450 are the amount of increase not the percent of increase
I thought it was 460 not 450......?
The percent change is (new-original)/original.
(3640 - 3250) / 3250 = 390 / 3250 = 39 / 325 = 3 / 25 = 12%
(4100 - 3640) / 3640 = 460 / 3640 = 46 / 364 = 23 / 182 = 12.637...%

The largest change came from 2001 to 2002.
#2018
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