Asked by Anonymous

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100. Find the percent of increase in the newspaper's circulation from 2000 to 2001 and from 2001 to 2002. Which period had the highest percent of increase, 2000 to 2001, or 2001 or 2002.

Answers

Answered by Farohw
% increase: calculate the difference then divide that number by the original amount and multiply by 100.

In 2000 - 3250
In 2001 - 3640

3640 - 3250 = 390

(390/3250)*100 = 12%

2001 - 3640
2002 - 4100


4100 - 3640 = 460

(460/3640) * 100 = 12.6%

You can answer the question.



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