Asked by Kitty

Under constant pressure, a small basketball pump is filled with helium, He,
gas; the helium is then forced out of a small aperture in 2 seconds. The same
pump is filled with hydrogen bromide, HBr, gas. Under the same pressure,
how long will it take to force this gas out?
Answered by DrBob222
No volume is listed; let's make up a volume, say 2 L for He, then the rate is (2L/2sec) = 1 L/s. Then
rate1/rate2 = sqrt(M2/M1)
1/rate 2 = sqrt(80.9/4)
solve for rate 2, then rate = 2L/sec and solve for sec. Post your work if get stuck.
Answered by Anonymous
4505
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