Asked by Eric

In a constant-pressure calorimeter, 50.0 mL of 0.300 M Ba(OH)2 was added to 50.0 mL of 0.600 M HCl. The reaction caused the temperature of the solution to rise from 24.50 degrees C to 28.59 degrees C. If the solution has the same density and specific heat as water, what is delta H for this reaction (per mole of H2O produced)? Assume that the total volume is the sum of the individual volumes. Delta H = ___ kJ/mol H2O
Answered by DrBob222
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q/0.03 mol = J/mol and divide by 1000 to convert to kJ.
Ba(OH)2 + 2HCl ==> BaCl2 + 2H2O
0.015mol...0.03......0.015..0.03 mol

Answered by Eric
wait i got (18g)(4.18J)(28.59-24.50) which brings me to 307.7316, is that right? is that when i divide by 0.03? and then divide by 1000? that brought me to 10.257 is this correct..?
Answered by Eric
I got it thanks!
Answered by v
DrBob222 you are very unclear.... why did you do all that?
Answered by Gerald
where did 0.03moles come from
Answered by Kate
IS this right?
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