Asked by megan
How many grams of nitric acid(HNO3) will be produced when 0.51 mol of dinitrogen pentoxide reacts with water to form nitric acid?
Answers
Answered by
Damon
mol mass N2O5 = 2*14 + 5*16 = 108 g/mol
mol mass HNO3 = 1 + 14 + 3*16 = 63 g/mol
for every N2O5 molecule you get two HNO3 molecules to balance the N atoms
so
.51 mol N2O5 ---> 1.02 mol HNO3
1.02mol * 63 g/mol = 64.26 g
mol mass HNO3 = 1 + 14 + 3*16 = 63 g/mol
for every N2O5 molecule you get two HNO3 molecules to balance the N atoms
so
.51 mol N2O5 ---> 1.02 mol HNO3
1.02mol * 63 g/mol = 64.26 g
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