A force of 310 N is applied horizontally to a crate in order to displace the crate 45.0 m across a level floor at a constant velocity. As a result of this work, the crate's internal energy is increased by an amount equal to 12 percent of the crate's initial internal energy. Calculate the initial internal energy of the crate. (Disregard the work done on the floor, and assume that all work goes into the crate.)

1 answer

To calculate the initial internal energy, we need to first find the work done on the crate. We can find the work done by using the equation:

W = Fd

Where W is the work done, F is the applied force, and d is the displacement.

W = 310 N × 45.0 m = 13950 J

From the problem statement, we know that the increase in the internal energy is 12 percent of the initial internal energy.

ΔE = 0.12 × E_initial

We can equate this to the work done:

13950 J = 0.12 × E_initial

Now, we can solve for the initial internal energy:

E_initial = 13950 J / 0.12 = 116250 J

So the initial internal energy of the crate is 116250 J.