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Question 5
A large crate has a mass of 214 kg. A horizontal force of positive 214 N is applied to it, causing it to accelerate at 0.130 m/s2 horizontally. What is the force of friction opposing the motion of the crate? Use the correct sign to indicate the direction of the force of friction. It is the sole force opposing the crate's motion in this direction. Assume the applied force is to the right and right is defined as the positive direction.
bobpursley
net force to right= mass*net acceleration to the right

214+Ff=mass*.130=214*.130
Ff=27.82-214= -186 N (and the sign is -, meaning to the left)

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