Question
how many liters of 0.100 M HCL would be required to react completely with 5.00 grams of calcium hydroxide?
Answers
Ca(OH)2 + 2HCl ==> CaCl2 + 2H2O
mols Ca(OH)2 = grams/molar mass = ??
mols HCl needed = mols Ca(OH)2 x (2 mols HCl/1 mol Ca(OH)2) = mols Ca(OH)2 x (2/1) = xx mols HCl
Molarity HCl = mols/L.
You know molarity and mols. Solve for Liters HCl. Check my
mols Ca(OH)2 = grams/molar mass = ??
mols HCl needed = mols Ca(OH)2 x (2 mols HCl/1 mol Ca(OH)2) = mols Ca(OH)2 x (2/1) = xx mols HCl
Molarity HCl = mols/L.
You know molarity and mols. Solve for Liters HCl. Check my
1.35
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