Asked by carlos
suppose you want to build a rectangular sandbox where the width is 4 ft less than the length and the diagonal is 4 ft longer than the length. what are the dimensions
Answers
Answered by
Damon
(x+4)^2 = x^2 + (x-4)^2
x^2 + 8 x + 16 = x^2 + x^2 - 8 x + 16
x^2 -16 x = 0
x = 0 or x = 16
so x = 16
12, 16, 20
x^2 + 8 x + 16 = x^2 + x^2 - 8 x + 16
x^2 -16 x = 0
x = 0 or x = 16
so x = 16
12, 16, 20
Answered by
Anonymous
Suppose you want to build a rectangular picture frame where the width is 2 centimeters less than the length and the diagonal is 2 centimeters longer than the length. What are the dimensions of the picture frame?
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