Asked by Dwi
An object ob 2 kg mass is initially at rest on the ground. then, the object is pulled up by a 20N force in 4s before it is finally released. the maximum height that the one object can reach is ...
Answers
Answered by
drwls
Remember that a weight force Mg = 19.6 N is also acting on the object in the opposite direction
While being pulled up, it accelerates at a rate
a = (F-M*g)/M = (20-19.6)/2 = 0.2 m/s^2
Its final velocity at release will be
a*t = 0.8 m/s.
From that release velocity, you can compute the height that it rises after release. It will acquire additional height (about 1.6 m) while being pulled
While being pulled up, it accelerates at a rate
a = (F-M*g)/M = (20-19.6)/2 = 0.2 m/s^2
Its final velocity at release will be
a*t = 0.8 m/s.
From that release velocity, you can compute the height that it rises after release. It will acquire additional height (about 1.6 m) while being pulled
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