Question

an object of mass 3 kg is at rest. Now a force of vectorS = 6t2^i + 4tj^ is applied on the object then velocity of object at t = 3 sec. is?

Answer 1

<b>F</b>F = m<b>a</b> = 6t^2<b>i</b> + 4t<b>j</b>
Since m=3,
<b>a</b> = 2t^2<b>i</b> + 4/3 t <b>j</b>
so,
<b>v</b> = 2/3 t^2 <b>i</b> + 2/3 t^2 <b>j</b>

Answer 2

Oops --
<b>v</b> = 2/3 t^3 <b>i</b> + 2/3 t^2 <b>j</b>

Answer 3

Dun public school