Question

Separate this redox reaction into its component half-reactions.
O2+2Cu---->2CuO
thought it was:
Oxidation 2e-+O2---->2O(-2)
Reduction Cu---->Cu(2+)-2e-
but this is wrong

Answer 1

For oxidation there are 4 e-'s.
Also, if you're typing this is on sapling make sure you include the states (eg: (aq), (g), (s))

Answer 2

on sapling its

Oxidation:
Cu --> Cu^2+ + 2e^-

Reduction:
O_2 + 4e^- -->2O^2-