Asked by Anonymous
Separate this redox reaction into its component half-reactions.
O2 + 2Zn -->2ZnO
O2 + 2Zn -->2ZnO
Answers
Answered by
DrBob222
O2 == O^2-
Zn ==> Zn^2+
You can balance.
Zn ==> Zn^2+
You can balance.
Answered by
Anonymous
Is it already balanced as is? When I tried I got it to all cancel out.
Answered by
DrBob222
I think it was balanced as you wrote it.
O2 + 4e==> 2O^2-
Zn ==> Zn2+ + 2e
Multiply equn 1 by 1 and eqn 2 by 2.
O2 + 4e ==> 2O^2-
2Zn ==> 2Zn^2+ + 4e and add
------------------
2Zn + O2 ==> 2ZnO
O2 + 4e==> 2O^2-
Zn ==> Zn2+ + 2e
Multiply equn 1 by 1 and eqn 2 by 2.
O2 + 4e ==> 2O^2-
2Zn ==> 2Zn^2+ + 4e and add
------------------
2Zn + O2 ==> 2ZnO
Answered by
Anonymous
sorry which of this is the oxidation reagent and reduction reagent
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