Asked by Odesa
N2O5 dissolved in CCl4 decomposes to give N2O4 and O2. The reaction is first order with a half-life of 1234 seconds. How long will it take, in seconds, for the concentration of N2O5 to fall to 1.1% of its initial value?
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
ln(No/N) = kt
Use No = 100 (you can choose any number)
N = 100 x 0.011 = ?
k from above.
t = solve for this.
ln(No/N) = kt
Use No = 100 (you can choose any number)
N = 100 x 0.011 = ?
k from above.
t = solve for this.
Answered by
Anonymous
DrBob222 explain better please
Answered by
Paul
So what is it? or how to guide in filling in the date in the equation?
Answered by
Paul
Thank you DrBob222,
the fraction left after t seconds is (1/2)^(t/1234)
(1/2)^(t/1234) = 0.011
t = 8028.84
the fraction left after t seconds is (1/2)^(t/1234)
(1/2)^(t/1234) = 0.011
t = 8028.84
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