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what is the % of CI in CCl4?
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Add atomic mass of C to 4 Cl.
Then %Cl = [(mass 4 Cl)/mass CCl4]*100 =
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Calculate the number of molecules in 3.11mol of CCL4
this is what I'm doing I got the molecular weight of CCL4 which is 181.88
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Calculate the total quantity of heat required to convert 25.0 g of liquid CCl4(l) from 25.0°C to gaseous CCl4 at 76.8°C (the
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find eq constant at 910K. CCl4 (g)--> <--CCl4(l)
given: Gf CCl4(g)= -53.7 Gf CCl4(l)= -68.6 G Products - G reactants = Delta G.
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Carbon tetrachloride (CCl4) is a liquid.
Assuming that CCl4 has a density of 1.595 g/mL what is the molarity of pure CCl4?
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