Question
5. A bomber is flying at a height of 9 km at 800 km/h. How far in front of the target should he
drop his bombs? show formulas*
drop his bombs? show formulas*
Answers
drwls
800 km/h = 222.2 m/s
Bomb fall time = sqrt(2H/g) = 42.9 s
(neglecting air resistance)
Bomb forward motion during fall time =
42.9*222.2 = 9533 m = 9.53 km
That is the "lead distance"
Bomb fall time = sqrt(2H/g) = 42.9 s
(neglecting air resistance)
Bomb forward motion during fall time =
42.9*222.2 = 9533 m = 9.53 km
That is the "lead distance"
Anonymous
123.456