a water bomber flying with a horizontal speed of 85m/s at a height of 3000 m drops a load on a fire below. how far in front of the target fire should the load be released?

Answer 1

how long does it take to fall 3000m?
h=1/2 a t^2...
t=sqrt(2*3000/9.8)

distance in front=85m/s*timeabove

Answer 2

it's asking for meters. the answer is 2103m just don't know how to get there.

Answer 3

Lord, I just told you how:
distanceinfront=85*sqrt(2*3000/9.8)

Answer 4

h=1/2 at^2
t^2=(2*3000)/9.8
t^2=612.244898
t=24.74358297sec
d=vt
d=85m/s*24.74358297s
d=2103meters

Answer 5

where do you find the answer key?