Asked by sumal

a water bomber flying with a horizontal speed of 85m/s at a height of 3000 m drops a load on a fire below. how far in front of the target fire should the load be released?
Answered by bobpursley
how long does it take to fall 3000m?
h=1/2 a t^2...
t=sqrt(2*3000/9.8)

distance in front=85m/s*timeabove
Answered by sumal
it's asking for meters. the answer is 2103m just don't know how to get there.
Answered by bobpursley
Lord, I just told you how:
distanceinfront=85*sqrt(2*3000/9.8)
Answered by vsb
h=1/2 at^2
t^2=(2*3000)/9.8
t^2=612.244898
t=24.74358297sec
d=vt
d=85m/s*24.74358297s
d=2103meters
Answered by dd
where do you find the answer key?
There are no AI answers yet. The ability to request AI answers is coming soon!