Asked by Sarah
Find the maximum volume of a cylindrical tin that has a total surface area of 600pi cm^2.
Answers
Answered by
Steve
a = 2pi r^2 + 2pi rh = 600pi
h = (600pi - 2pi r^2)/(2pi*r)
= 300/r - r
v = pi r^2 h
= pi r^2 (300/r - r)
= 300pi r - pi r^3
dv/dr = 300pi - 3pi r^2
dv/dr = 0 when r = 10
so, h = 20
max v = pi * 100 * 20 = 200pi
h = (600pi - 2pi r^2)/(2pi*r)
= 300/r - r
v = pi r^2 h
= pi r^2 (300/r - r)
= 300pi r - pi r^3
dv/dr = 300pi - 3pi r^2
dv/dr = 0 when r = 10
so, h = 20
max v = pi * 100 * 20 = 200pi
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