Asked by Destry
Describe how to make 175mL of a .10M tin(II) chloride solution??
Answers
Answered by
DrBob222
You want 0.1 mol/L soln. The trick is in how you do it.
How many mols do you want. That molos = M x L = 0.1 x 0.175 = 0.0175 mols.
Then mols = grams/molar mass. With mols and molar mass you can calculate grams SnCl2.
First let me tell you what NOT to do. You DON'T weigh out the proper amount SnCl2 and add 175 mL H2O. This is what instructors try to impress on you. So what DO you do.
Weigh out the appropriate amount of SnCl2 and place in a 175 mL volumetric flask (we'll assume they make such things). Then add some water and swirl until all of the SnCl2 is dissolved, then add more H2O until the flask has exactly 175 mL H2O in it. Note that this is not the same thing as adding 175 mL H2O.
How many mols do you want. That molos = M x L = 0.1 x 0.175 = 0.0175 mols.
Then mols = grams/molar mass. With mols and molar mass you can calculate grams SnCl2.
First let me tell you what NOT to do. You DON'T weigh out the proper amount SnCl2 and add 175 mL H2O. This is what instructors try to impress on you. So what DO you do.
Weigh out the appropriate amount of SnCl2 and place in a 175 mL volumetric flask (we'll assume they make such things). Then add some water and swirl until all of the SnCl2 is dissolved, then add more H2O until the flask has exactly 175 mL H2O in it. Note that this is not the same thing as adding 175 mL H2O.
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