Asked by lily

describe how you would make a 2.5L of a .100M KCL solution from a 5.5M stock solution

14 years ago

Answered by MathMate

2.5 l of 0.1M solution contains 0.25 moles.

Volume of 5.5M stock solution required
= 0.25/5.5 * 1000 ml

14 years ago

Answered by Zap Mink

45.454545

9 years ago

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