Asked by Anonymous
                what volume of 14.8M ammonia is required for preparation of 3.1g of [cu(nh3)4]so4.h2o
            
            
        Answers
                    Answered by
            DrBob222
            
    mols [Cu(NH3)4]SO4.H2O  = grams/molar mass.
You need 4x that number mols NH3. Do you know why?
M NH3 = mols NH3/L NH3. You know mols and M solve for L and convert to mL (the problem doesn't tell you the unit for volume).
    
You need 4x that number mols NH3. Do you know why?
M NH3 = mols NH3/L NH3. You know mols and M solve for L and convert to mL (the problem doesn't tell you the unit for volume).
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