Asked by Czar
What volume of ammonia gas at STP is required to neutralize 40 cubic centimetres of 2 Molar sulphuric acid?
Answers
Answered by
DrBob222
2NH3 + H2SO4 ==>(NH4)2SO4
mols H2SO4 = M x L = ?
mols NH3 required = 2 x mols H2SO4 which you find by using the coefficients in the balanced equation; i.e., mols NH3 = molx H2SO4 x (2 mols NH3/1 mol H2SO4) = ?
Then 1 mol NH3 gas at STP occupies 22.4 L; therefore, ? mols NH3 gas will occupy ? L.
mols H2SO4 = M x L = ?
mols NH3 required = 2 x mols H2SO4 which you find by using the coefficients in the balanced equation; i.e., mols NH3 = molx H2SO4 x (2 mols NH3/1 mol H2SO4) = ?
Then 1 mol NH3 gas at STP occupies 22.4 L; therefore, ? mols NH3 gas will occupy ? L.
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