Endothermic reaction equilibrium:

Question

BiCl3(aq) + H2O(g) = BiOCl(s) +2HCL(aq) + 2 HCl at a point at which the sollution is colorless and a small minute amoount of BiOCl(s) is observed.
for the folowing questions 1to 5:
a. state which way the reaction shift in terms of LeChateliers explain why
b. state what would be observed
stress imposed on the system
1. water vapor is added
2. a few drops of concentrated HCl is added to the system from part a my answer is it will shift to the right
3. a few drops of concentrated NaOH is added to the system in part b my answer is it will shift to the right
4. heat is added to the original reaction my answer is since heat is added to the reactants the equilibrium will shift to the product.
5. more BiOCl is added to the reaction my answer is it will shift to reactant side
pls correct my answers only i really don't know what to observe based on that reaction. this is a prelab question before we have the experiment thanks for any help you can give

Answer 1

Let me make a few observations.
1. With no caps and no punctuation plus incomplete sentences it makes it difficult to know what you do and don't understand.
2. You think adding HCl will shift the reaction to the right BUT
3. You think adding NaOH will shif the reaction to the right.
With HCl and NaOH being complete opposites, how can you give the questions the same answer. Of course that means that at least one of them will be right and I suppose 50% isn't bad.
4 is correct.
5 is not. Adding a SOLID doesn't change the equilibrium. This is in equilibrium with a small amount of solid BiOCl in place. It will stay in equilibrium as long as a "little" BiOCl is present. Adding more or taking away some has no effect on the equilibrium.