How many grams of chlorine gas must react to give 4.82g of BiCl3?

Question

2Bi(s)+3Cl2(g)→2BiCl3(s)

My answer was wrong/please review and tell me where I went wrong.

4.82g BiCl3*1mol BiCl3/215.33g BiCl3*3 mol Cl2/2 mol Bicl3* 70.9g Cl2/1 mol Cl2=6.50 g Cl2

Answer 1

I think you problem is the molar mass of BiCl3. I think that is 315.34
The rest of it looks ok, at least at first glance.

Answer 2

I just calculated it wrong.
My answer should have been 1.63g of Cl2

Answer 3

1.63g of Cl2