Asked by gabby
susan throws a softball upward into the air at a speed of 32 feet per second from a 8 foot platform. the distance upward that the ball travels is given by the function. d(t)=-16t^2+32t+8. What is the maximum height of the softball? how many seconds does it take to reach the ground after first being thrown.
Answers
Answered by
Steve
as you know, the vertex of a parabola occurs at x = -b/2a.
Here, that is -32/-32 = 1
d(1) = 24
solving d=0 for t, we have t = 1+√3/2
Here, that is -32/-32 = 1
d(1) = 24
solving d=0 for t, we have t = 1+√3/2
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