Asked by Anonymous
A large block P executes horizontal simple harmonic motion as it slides across a frictionless surface with a frequency f = 1.7 Hz. Block B rests on it, as shown in the figure, and the coefficient of static friction between the two is ìs=0.64. (b) What is the maximum force of static friction for a 6.7 kg mass?
Answers
Answered by
bobpursley
friction=mu*massB*g
you are given massB, mu, and you should know g.
you are given massB, mu, and you should know g.
Answered by
bobpursley
The wording here is a bit suspicious. Maximum acceleration occurs when the amplitude is maximum, and it is acceleration=-(2PI*f)^2*maxAmplitude
so when you know the maxAmplitude, you can figure acceleration, which is of course force=mass*acceleration, and the force on the block B is that force. If it is greater than friction, the block slides off.
so when you know the maxAmplitude, you can figure acceleration, which is of course force=mass*acceleration, and the force on the block B is that force. If it is greater than friction, the block slides off.
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