Asked by nic
A person with a density of 980 kg/m3 floats in seawater of density 1025 kg/m3. What fraction of the person is submerged?
Answers
Answered by
Elena
weight=buoyant force
mg= F
d₁•V•g =k•d₂•V•g
k= d₁/d₂ =980/1025 =0.956
mg= F
d₁•V•g =k•d₂•V•g
k= d₁/d₂ =980/1025 =0.956
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