Asked by Anonymous
The density of a gas is 1.96 g L–1 at 1.00 atm and 0
°C. What is the density of this gas at 0.855 atm and 25.0
C?
°C. What is the density of this gas at 0.855 atm and 25.0
C?
Answers
Answered by
DrBob222
Two ways to do this. The long way, but easier to explain, and the short way but harder to explain. The long way first:
The general gas formula can be modifed to
P*M = dRT where M is molar mass and d is density in g/L. Substitute into that and solve for M. Then use the same equation, substitute the new conditions and solve for the new density.
Shorter way.
1.96 x (pres factor) x (Temp factor) =
1.96 g/L x (0.855/1) x (273/298) = ?
How does the shorter way work?
P factor. P decreases therefore L increases and density gets smaller so the factor must be less than 1 which makes the small number go in the numerator.
T factor. T increases from 273 to 298, L must increase, larger L means smaller density so the T factor must be less than 1 which makes the small number go on top.
The general gas formula can be modifed to
P*M = dRT where M is molar mass and d is density in g/L. Substitute into that and solve for M. Then use the same equation, substitute the new conditions and solve for the new density.
Shorter way.
1.96 x (pres factor) x (Temp factor) =
1.96 g/L x (0.855/1) x (273/298) = ?
How does the shorter way work?
P factor. P decreases therefore L increases and density gets smaller so the factor must be less than 1 which makes the small number go in the numerator.
T factor. T increases from 273 to 298, L must increase, larger L means smaller density so the T factor must be less than 1 which makes the small number go on top.
Answer
1.8
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