Asked by anna
How would I solve for t if y equals 720 minutes of daylight and t=the number of days in 2012
720 = 713.7+152.7 sin [(2pi/366)(t-80.75)]
720 = 713.7+152.7 sin [(2pi/366)(t-80.75)]
Answers
Answered by
anna
this problem is modelling daylight hours using the form y = d+a sin[b(t-c)], btw
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