Asked by Jessica
A rock is thrown straigh down from a height of 480 feet with an initial velocity of 16 feet per second. How long does it take to hit the ground and with what speed does it hit the ground?
Answers
Answered by
Steve
the height h at time t is given by
h(t) = 480 - 16t - 16t^2
when it hits the ground, h=0, so solve
30-t-t^2 = 0
(6+t)(5-t) = 0
t = 5 sec.
the velocity v at time t is
v = -16 - 32t
v(5) = -16 - 160 = -176 ft/s
h(t) = 480 - 16t - 16t^2
when it hits the ground, h=0, so solve
30-t-t^2 = 0
(6+t)(5-t) = 0
t = 5 sec.
the velocity v at time t is
v = -16 - 32t
v(5) = -16 - 160 = -176 ft/s
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