Asked by Anonymous
A tennis ball is thrown straight up with an initial speed of 22.5 m/s. It is caught at the same distance above the ground where it was thrown.
How high did the ball rise?
How high did the ball rise?
Answers
Answered by
oobleck
initial KE = 1/2 mv^2
PE at top of arc = mgh
set them equal to find h
PE at top of arc = mgh
set them equal to find h
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