Asked by Sandara
A tennis ball is thrown up with an initial speed of 22.5m/s. It is caught at the same distance above the ground.
A) how high does the ball rise
B) how long does the ball remain in the air?
A) how high does the ball rise
B) how long does the ball remain in the air?
Answers
Answered by
bobpursley
initial KE=final PE
1/2 m 22.5^2=m g h
solve for h.
time in air:
hf=hi+vi*t-4.9t^2
hf=hi and vi is given, solve for t.
1/2 m 22.5^2=m g h
solve for h.
time in air:
hf=hi+vi*t-4.9t^2
hf=hi and vi is given, solve for t.
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