Question

a 2.00kg copper plate with an initial temperature of 20.0 degrees Celsius slides with a constant velocity down a 150m long surface that is inclined at 30 degrees angle to the horizontal. If the mechanical energy lost by the system due to friction is absorbed by the copper to change its temperature, what is the new temperature of the plate when it is at the bottom of the incline?

Answer 1

mechinical energy=mass*g*height=mg*150sin30

set that equal to

mass*specificeheat*(Tf-Ti) solve for Tf