Question
A thin copper plate of diameter 11.0 cm is charged to 9.00 nC. What is the strength of the electric field 0.1 mm above the center of the top surface plate?
Answers
bobpursley
Well, the charge distributes on both sides of the plate, so
E=Q/(area*2*epsilion)
area=PI(.11)^2, Q=9nC
E=Q/(area*2*epsilion)
area=PI(.11)^2, Q=9nC