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A thin copper plate of diameter 11.0 cm is charged to 9.00 nC. What is the strength of the electric field 0.1 mm above the center of the top surface plate?
8 years ago

Answers

bobpursley
Well, the charge distributes on both sides of the plate, so
E=Q/(area*2*epsilion)
area=PI(.11)^2, Q=9nC
8 years ago

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