Ask a New Question

Question

The third term of a geometric series is 24 and the fourth term is 36. Determine the sum of the first 10 terms. Express your answers as an exact fraction.
12 years ago

Answers

Steve
T4 = T3*r, so r = 36/24 = 3/2

T3 = ar^2, so 24 = a(9/4), so a=32/3

S10 = 32/3 * (1-(3/2)^10)/(1 - 3/2) = 58025/48

seems clumsy, so better check my math.
12 years ago

Related Questions

The third term of a geometric series is 24 and the fourth term is 36. Determine the first term and c... The first term of a geometric progression is more than the third term by 12. The fourth term is more... The fifth term of an geometric sequence is 4375 and the second term is 35.find (a)the third term (b)... The first term of a geometric series is 3 the last term is 768 if the sum is 1533 The first term of a geometric progression is 6. If it's common ratio is 2,find the sixth term The 5th term in a geometric sequence is 140. The 7th term is 35. What are the possible values of the... the first term of a geometric sequence is 5 and the common ratio is 6. 1) create an equation for th... The first term of a geometric sequence is 5 and the common ratio is −3. What is the sum o...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use