Asked by bahle
the third term of a geometric sequence is 6 and the sixth term is 3 over 32. Determine the first terms and the general term Tn?
Answers
Answered by
Damon
1 a
2 ar
3 ar^2
4 ar^3
5 ar^4
6 ar^5
n ar^(n-1)
so
ar^2 = 6
ar^5 = 3/32
so
a = 6/r^2
(6/r^2)r^5 = 3/32
6/r^3 = 3/32
r^3 = 32*2 = 64
r = 4
then
a = 6/16 = 3/4
so
Tn = (3/4)4^(n-1)
2 ar
3 ar^2
4 ar^3
5 ar^4
6 ar^5
n ar^(n-1)
so
ar^2 = 6
ar^5 = 3/32
so
a = 6/r^2
(6/r^2)r^5 = 3/32
6/r^3 = 3/32
r^3 = 32*2 = 64
r = 4
then
a = 6/16 = 3/4
so
Tn = (3/4)4^(n-1)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.