solve the following exponential equation. exact answers only.

Um....where does 1-9x and 2x connect? Are they just separate algebraic expressions? And where does e come into play? Thanks

Ok, it didn't turn out right. This is the question.

2 with the 1-9x above the 2 = e with 2x above the e.

Hope this makes more sense now and you can help me and show me how you came about getting the answers.

Thanks!!!!

2^(1-9x) = e^2x ??? is that what you mean?

if so then

ln (e^2x) = 2x ln e = 2x
and
ln [ 2^(1-9x) ] = (1-9x) ln 2 = .693(1-9x)

so
2x = .693 (1-9x)
2x = .693 - 6.24 x
8.24 x = .693
x = .0841

Yes, thanks. I am not quite sure how to make some of the signs when posting my questions here. I am probably older than most and really trying to learn to post them right. Is there a place that you might can refer me to, so that I can try and learn the right signs and symbols????

To solve the exponential equation 1-9x/2 = e, we can follow these steps:

Step 1: Move the constant term to the right side of the equation.
1 - 9x/2 = e
1 = e + 9x/2

Step 2: Multiply both sides of the equation by 2 to get rid of the fraction.
2(1) = 2(e + 9x/2)
2 = 2e + 9x

Step 3: Move the term with x to the left side of the equation and the constant term to the right side.
9x = 2 - 2e

Step 4: Divide both sides of the equation by 9 to isolate x.
9x/9 = (2 - 2e)/9
x = (2 - 2e)/9

So, the exact solution to the exponential equation 1-9x/2 = e is x = (2 - 2e)/9.

Please note that this answer may vary depending on the context of the equation and the values of e.