Asked by Austin
solve the following exponential expression.
e^x+e^-x=6
e^x+e^-x=6
Answers
Answered by
Reiny
e^x + e^-x = 6
e^x + 1/e^x = 6
hint:
let e^x = y
y + 1/y = 6
each term by y
y^2 + 1 = 6y
y^2 - 6y + 1 = 0
solve for y, then sub back into e^x
e^x + 1/e^x = 6
hint:
let e^x = y
y + 1/y = 6
each term by y
y^2 + 1 = 6y
y^2 - 6y + 1 = 0
solve for y, then sub back into e^x
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