Asked by jay
COULD YOU FURTHER EXPLAIN HOW MANY BTU ARE REQUIRED TO RAISE THE TEMP OF500 GALLONS OF WATER FROM 70 DEGRESS TO 160 DEGREES FAHRENHIET
Answers
Answered by
Damon
As Bob Pursley said
In general:
heat=mass*specificeheat*changetemp
or
heat in = mass of water * specific heat of water * (Final temp -original temp)
In these strange English units
weight in pounds is used for mass
weight = 500 gal * 8.31 pounds/gal = 4155 pounds
specific heat of water in these units = 1 BTU/pound
change in temp = 160 - 70 = 90 degrees F
so
BTU = 4155 * 1 * 90
= 373,950 BTU
In general:
heat=mass*specificeheat*changetemp
or
heat in = mass of water * specific heat of water * (Final temp -original temp)
In these strange English units
weight in pounds is used for mass
weight = 500 gal * 8.31 pounds/gal = 4155 pounds
specific heat of water in these units = 1 BTU/pound
change in temp = 160 - 70 = 90 degrees F
so
BTU = 4155 * 1 * 90
= 373,950 BTU
Answered by
Jason
There is no change of state in this problem. If you were changing water to vapor that would require an extra 970 btu/lb or 4,030,350 on top of the 373,950 grid.
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