Asked by amanda78
A sample of potassium hydrogen oxalate, KHC204, weighing 0.717 g, was dissolved in water and titrated with 18.47 mL of an NaOH solution. Calculate the molarity of the NaOH solution.
Answers
Answered by
DrBob222
KHC2O4 + NaOH ==> NaKC2O4 + H2O
mols KHC2O4 = grams/molar mass = ?
mols NaOH = mols KHC2O4(see the coefficients in the balanced equation).
Then M NaOH = mols NaOH/L NaOH and solve for M
mols KHC2O4 = grams/molar mass = ?
mols NaOH = mols KHC2O4(see the coefficients in the balanced equation).
Then M NaOH = mols NaOH/L NaOH and solve for M
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