Asked by Steve
Potassium hydrogen phthalate (molar mass = 204.2 g/mol is used to standardize sodium hydroxide. If 23.67 ml of NaOH (aq) is required to titrate 0.7719 g KHP to the equivalence point, what is the concentration of the NaOH(aq)?
HC8H4O4-(aq) + OH-(aq) = C8H4O4^2-(aq) + H2O(l)
HC8H4O4-(aq) + OH-(aq) = C8H4O4^2-(aq) + H2O(l)
Answers
Answered by
DrBob222
Since 1 mol of the KHP reacts with 1 mol NaOH, you can use,
mLbase x Molaritybase = mLacid x Molarityacid.
You have three and can calculate the fourth.
mLbase x Molaritybase = mLacid x Molarityacid.
You have three and can calculate the fourth.
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