ANGLE=ang
ang<80>/f(x>(l/2)(ff)(mg)
<260>(1.333%)(3.7)
%=fn/viv<0.16/.409n)
[pi^2](fn(80))
ANS: 41.19
A sled is pulled across a horizontal snow surface with a constant velocity. The force being applied is 80 N at an angle of 53 degrees to the ground. What is the magnitude of the force of friction of the snow acting on the sled?
1 answer
1 answer