Asked by Anonymous


For the emission spectrum of Be3+, calculate the lowest wavenumber νˉ (in inverse meters) of light produced by electron transitions between n=2, n=3, and n=4.

I don't want to know the answer... Just tell me what I would need to do to work it out :) pls?? X

Answers

Answered by amar chauhan
8.56*10^6
by amar chauhan
Answered by 123
that's not an answer!
Answered by 123
sry. i meant that that wasn't the explanation for how to do it
Answered by Anonymous
concepts??
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